Data Interpretation

Study the following information to answer the given questions. Percentage of students in various courses (A, B, C, D, E, F) and Percentage of the girls out of these.



1. For which pair of courses is the number of boys the same?
a) E & F
b) A & D
c) C & F
d) B & D
e) None of these

2. For course D what is the respective ratio of boys and girls?
a) 3 : 4
b) 4 : 5
c) 3 : 5
d) 5 : 6
e) None of these

3. How many girls are in course C?
a) 44
b) 16
c) 40
d) 160
e) None of these

4. For course E, the number of girls is how much per cent more than the boys for course E?
a) 250
b) 350
c) 150
d) 80
e) None of these

5. For which course is the number of boys the minimum?
a) E
b) F
c) C
d) A
e) None of these

Answers

1. (c) Explanation: Number of boys in pair E and F is = 1200 × 35100−800 × 14100 and = 1200×13100−800×14100 = (144 – 112) and (156 – 112) = 32 and 44
 Number of boys in pair A and D is = 1200 ×20100−800 × 14100
and = 1200 × 35100−800 × 14100 = (60-16) and (156-112) = 44 and 44

2.  (a) Explanation: Number of girls in course E = 1200 × 35100−800 × 30100 = 420 – 240 = 180 Number of girls in course D = 800 ×30100 = 240 Required ratio = 180: 240 = 3 : 4

3. (b) Explanation: Number of girls in course C = 800 × 2100 = 16

4. (a) Number of girls in course E = 800 ×14100 = 112
 Number of boys in course E = 1200 × 12100 = 144 = 144 -112 = 32
Required percentage = = 112−32 × 100100 = 250 %

5. (d) Explanation: Number of boys in course A = 1200 × 20100 – 800 × 30100 = 240 – 240 = 0
Number of boys in course B = 1200 × 15100 – 800 × 10100 = 180 – 80 = 100
Number of boys in course C = 1200 × 5100 – 800 × 2100 = 60 – 16 = 44
Number of boys in courses D = 1200 × 35100 – 800 × 30100 = 420 – 240 = 180
Number of boys in courses E = 1200 × 12100 – 800 × 14100 = 144 – 112 = 32


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