**Direction(1-5): Select the related letters/word/number from the given alternative.**

1. F × H : 21 × 19 : : M × O : ?

(a) 13 × 15

(b) 14 × 12

(c) 20 × 19

(d) 21 × 23

2. NPRT : MNOP : : ? : EFGH

(a) FHJL

(b) FHIK

(c) FHKM

(d) FGKL

3. 4 : 8 : : 1 : ?

(a) 9

(b) 3

(c) 1

(d) 0

4. 10 : 14 : : 7 : ?

(a) 9

(b) 13

(c) 15

(d) 17

5. LIME : 20 : : LEMON : ?

(a) 60

(b) 30

(c) 40

(d) 50

**Direction (6 - 7): Which one set of letters when sequentially placed at the gaps will complete the given letter series?**

6. ab_accab_acc_bba_cabba_c

(a) bbacc

(b) acbcc

(c) bcabb

(d) bcbba

7. aa_abba_babbaa_ab_

(a) babb

(b) baba

(c) aaba

(d) abaa

8. If FUTURE is coded as UFTUER then how will NATURE be coded ?

(a) ANUTER

(b) ANTURE

(c) ANTUER

(d) ANUTRE

9. If TEA is coded as 100, then how will you code FAT?

(a) 120

(b) 150

(c) 140

(d) 130

10. If A represents ‘×’, B represents ‘÷’, C represents ‘+’ and D represents ‘-‘’, then find the value of 2 A 8 D 5 C 9 B 3?

(a) 11

(b) 13

(c) 15

(d) 14

**Answers:**

1: (b)

21 and 19 represents the number of letters that come after F and H in alphabetical sequence.

2: (a)

In the group MNOP, the letters are shifted +1, +2, +3, +4 places in alphabetical sequence to get NPRT. Similarly, EFGH can be converted to FHJL

3: (c)

4 and 8 are 22 and 23 respectively. So, 12 and 13 are the next numbers in the group.

4: (a)

10/2 + 2 = 7

Therefore, 14/2 + 2 = 9

5: (b)

The sum of alphabetical positions of L, I, M and E is 12+9+13+5=39. So, 39+1=40/2=20.

The sum of alphabetical positions of L, E, M, O and N is 12+5+13+15+14=59. So, 59+1=60/2=30.

6: (a)

The pattern here will be ‘abbaccabbacc’

7: (a)

The pattern here will be ‘aababb’.

8: (c)

In FUTURE, first two letters are reversed, last two letters are reversed and middle two letters are unchanged. So, NATURE will be coded as ANTUER.

9: (a)

In TEA, the alphabetical positions of T, E and A are 20, 5 and 1. The positions numbers are multiplied to get the code as 100. Similarly, FAT can be coded as 120.

10: (d)

2 A 8 D 5 C 9 B 3 = 2 × 8 - 5 + 9 ÷ 3 = 16 – 5 + 3 = 14