### Machine Input for IBPS Exams 2017

Directions (1-5): Study the following information to answer the given questions:

A word and number arrangement machine when given an input line of words and numbers rearranges them following a particular rule. The following is an illustration of input and rearrangement. (All the numbers are two-digit numbers.)
Input: sine 88 71 cos theta 14 56 gamma delta 26
Step I. cos sine 71 theta 14 56 gamma delta 26 88
Step II. delta cos sine theta 14 56 gamma 26 88 71
Step III. gamma delta cos sine theta 14 26 88 71 56
Step IV. sine gamma delta cos theta 14 88 71 56 26
Step V. theta sine gamma delta cos 88 71 56 26 14
As per the rule followed in the above steps, find out in each of the following questions the appropriate steps for the given input.
Input for the questions:
Input: for 52 all 96 25 jam road 15 hut 73 bus stop 38 46
(All the numbers given in the arrangement are two-digit numbers.)

Q1. Which word/number would be at 8th position from the right in step IV?
(a) 15
(c) hut
(d) jam
(e) stop

Q2. Which step number would be the following output?
bus all for 52 25 jam road 15 hut stop 38 46 96 73
(a) There will be no such step
(b) III
(c) II
(d) V
(e) VI

Q3. Which of the following would be step VII?
(a) stop road jam hut for bus all 15 96 73 5246 38 25
(b) road jam hut for bus all stop 15 25 38 46 52 73 96
(c) stop road jam hut for bus all 96 73 52 46 38 25 15
(d) jam hut for bus all 25 road stop 15 96 73 52 46 38
(e) There will be no such step

Q4. Which word/number would be at 6th position from the left in step V?
(a) 25
(b) stop
(c) jam
(d) all

Q5. Which of the following would be step III?
(a) hut for bus all 25 jam road 15 stop 38 96 73 52 46
(b) for bus all 25 jam road 15 hut 38 stop 96 46 73 52
(c) hut for bus all jam road 15 stop 38 96 73 52 46 25
(d) for bus all 25 jam road 15 hut stop 38 46 96 73 52
(e) None of the above

Directions (6-10): Study the following information carefully and answer the given questions:

A word and number arrangement machine when given an input line of words and numbers rearranges them following a particular rule. The following is an illustration of input and rearrangement. (All the numbers are two-digit numbers.)
Input: gate 20 86 just not 71 for 67 38 bake sun 55
Step I: bake gate 20 just not 71 for 67 38 sun 55 86
Step II: for bake gate 20 just not 67 38 sun 55 86 71
Step III: gate for bake 20 just not 38 sun 55 86 71 67
Step IV: just gate for bake 20 not 38 sun 86 71 67 55
Step V: not just gate for bake 20 sun 86 71 67 55 38
Step VI: sun not just gate for bake 86 71 67 55 38 20
And Step VI is the last step of the above input.
As per the rules followed in the above steps, find out in each of the following questions the appropriate step for the given input.
Input: 31 rise gem 15 92 47 aim big 25 does 56 not 85 63 with moon

Q6. How many steps will be required to complete the rearrangement?
(a) Eight
(b) Six
(c) Seven
(d) Five
(e) None of the above

Q7. Which word/number would be at 7th position from the left in step IV?
(a) rise
(b) aim
(c) big
(d) 15
(e) 47

Q8. Which step number is the following output?
rise not moon gem does big aim 15 with 92 85 63 56 47 31 25
(a) Step V
(b) Step VII
(c) Step IV
(d) Step VIII
(e) There is no such step.

Q9. Which of the following represents the position of ‘92’ in step VI?
(a) Ninth from the left
(b) Fifth from the right
(c) Sixth from the right
(d) Ninth from the right
(e) Seventh from the left

Q10. Which word/number would be at 5th position from the right in the last step?
(a) gem
(b) 63
(c) 56
(d) 85
(e) does

1-5

Logic: After careful analysis of the given input and various steps of rearrangement it is evident that in each step one word and one number are rearranged. The words are rearranged from left in alphabetical order and the numbers are rearranged from the right in descending order but in the final step the words get rearranged in alphabetical order in reverse manner and numbers appear in descending order.

Input: for 52 all 96 25 jam road 15 hut 73 bus stop 38 46
Step I: all for 52 25 jam road 15 hut 73 bus stop 38 46 96
Step II: bus all for 52 25 jam road 15 hut stop 38 46 96 73
Step III: for bus all 25 jam road 15 hut stop 38 46 96 73 52
Step IV: hut for bus all 25 jam road 15 stop 38 96 73 52 46
Step V: jam hut for bus all 25 road 15 stop 96 73 52 46 38
Step VI: road jam hut for bus all 15 stop 96 73 52 46 38 25

Step VII: stop road jam hut for bus all 96 73 52 46 38 25 15

1-b
2-c
3-c
4-a
5-d

6-10

Logic: After careful analysis of the given input and various steps of rearrangement it is evident that in each step one word and one number are rearranged. The words are rearranged from left in alphabetical order and the numbers are rearranged from the right in descending order but in the final step the words get rearranged in alphabetical order in reverse manner and numbers appear in descending order.

Input: 31 rise gem 15 92 47 aim big 25 does 56 not 85 63 with moon
Step I: aim 31 rise gem 15 47 big 25 does 56 not 85 63 with moon 92
Step II: big aim 31 rise gem 15 47 25 does 56 not with moon 92 85 63
Step III: does big aim 31 rise gem 15 47 25 56 not with moon 92 85 63
Step IV: gem does big aim 31 rise 15 47 25 not with moon 92 85 63 56
Step V: moon gem does big aim 31 rise 15 25 not with 92 85 63 56 47
Step VI: not moon gem does big aim rise 15 25 with 92 85 63 56 47 31
Step VII: rise not moon gem does big aim 15 with 92 85 63 56 47 31 25

Step VIII: with rise not moon gem goes big aim 92 85 63 56 47 31 25 15

6-a
7-d
8-b
9-c
10-c